Converting Square Roots to Iota

$2i$

$-2i$

$3i$

$1i$

$\sqrt{60}i$

$-\sqrt{60}i^2$

$-\sqrt{60}i$

$\sqrt{60}i^2$

$\dfrac{14}{19}i$

$\dfrac{14}{-19}i$

$\dfrac{19}{14}i$

-$\dfrac{19}{14}i$

-$\dfrac{15}{3}i$

$\dfrac{3}{15}i$

$\dfrac{15}{3}i$

$\dfrac{3}{-15}i$

$-\sqrt{28}i$

$-\sqrt{28}i^2$

$\sqrt{28}i^2$

$\sqrt{28}i$