Converting Square Roots to Iota

$10 + i$

$10i^2$

$-10i$

$10i$

$-\sqrt{65}i^2$

$\sqrt{65}i^2$

$\sqrt{65}i$

$-\sqrt{65}i$

$\dfrac{8}{20}i$

$\dfrac{-20}{8}i$

$\dfrac{20}{8}i$

-$\dfrac{8}{20}i$

$19i$

$18i$

$-19i$

$20i$

$\dfrac{18}{16}i$

$\dfrac{-16}{18}i$

$\dfrac{16}{18}i$

-$\dfrac{18}{16}i$